............................................................(3)
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where A,B are two arbitrary constants.
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To find A,B we need two initial conditions or boundary conditions
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We know
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..............................................(4)
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We need one more condition. To get this, we need to find the current coming out of the voltage source, as shown in the previous case.
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Replace the circuit looking towards the terminal node from node k by an equivalent thevenin resistance Rk. Hence,
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Where Rk-1 is the equivalent resistance at node (k-1).
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or,
..........................................................(5)
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with boundary condition RN = R
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Hence,
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etc.
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If we let RN-i = C N-i R
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i.e. Rj = C j R...............................................................................(6)
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.......................................................................(7)
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with CN=1
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Iteratively solve (7) to get C1 and hence R1 = C 1 R
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Once R1 is obtained
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Applying KCL to node 1
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or, .........................................(8)
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Using (8) in (3) gives
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.............................................(9)
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Use (4) and (9) to get A,B ; substitute these values of A,B back in (3) to get the node voltage for Vk for any k in (1,2,...........N).
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